maka luas permukaan prisma adalah...
- Sisi belah ketupat
[tex] \tt = \sqrt{ {(6 \div 2)}^{2} + {(8 \div 2)}^{2} } [/tex]
[tex] \tt = \sqrt{ {3}^{2} + {4}^{2} } [/tex]
[tex] \tt = \sqrt{9 + 16} [/tex]
[tex] \tt = \sqrt{25} [/tex]
= 5 cm
- Luas permukaan
[tex] \tt = \not2 \times \frac{d_{1} \times d_{2}}{\not2} + 4 \times s \times t.prisma[/tex]
= 8 cm × 6 cm + 4 × 5 cm × 5 cm
= 48 + 100 cm²
= 148 cm²
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]
Menentukan sisi belah ketupat:
- s² = 4² + 3²
- s² = 16 + 9
- s² = 25
- s = √25
- s = 5 cm
..
Menentukan luas permukaan prisma:
Lp = 2(luas alas) + Keliling alas × tinggi prisma
Lp = 2(½ × d1 × d2) + 4s(t)
Lp = 2(½ × 8 × 6) + 4(5)(5)
Lp = 2(24) + 100
Lp = 48 + 100
Lp = 148 cm²
opsi B
[answer.2.content]
